What is the answer to solvefor f,f=ln((1+i)^n) ?

The answer to solvefor f,f=ln((1+i)^n) is f=ln(1+i)n

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solvefor f,f=ln((1+i)^n)

solve for

f, f = ln ((1 + i)^{n})

f = ln (1 + i) n

Solution steps

f = ln ((1 + i)^{n})

Apply log rule

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x),

assuming

x \geq 0

f = ln (1 + i) n

2 ln (x) - 2 ln (\frac{y}{x})

\frac{1}{2} (ln (61) - ln (6))

f (y) = ln (y - 4) + ln (y + 4)

- lo g_{10} (8.5 \cdot 1 0^{- 3})

4 ln (- 2) + ln (- 3)

What is the answer to solvefor f,f=ln((1+i)^n) ?
The answer to solvefor f,f=ln((1+i)^n) is f=ln(1+i)n