What are the solutions to the equation (s-9)(s-1)=0 ?

The solutions to the equation (s-9)(s-1)=0 are s=9,s=1

Find the zeros of (s-9)(s-1)=0

The zeros of (s-9)(s-1)=0 are s=9,s=1

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(s - 9) (s - 1) = 0

s = 9, s = 1

Solution steps

(s - 9) (s - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s - 9 = 0 or s - 1 = 0

Solve

s - 9 = 0 : s = 9

Solve

s - 1 = 0 : s = 1

The solutions to the quadratic equation are:

s = 9, s = 1

lo g_{2} (10) = x

25 x^{2} + 40 x + 16

\frac{x}{5} - 2 = \frac{x}{3}

∣ x - 3 ∣ > 1

\frac{4 + 6 i}{i}

What are the solutions to the equation (s-9)(s-1)=0 ?
The solutions to the equation (s-9)(s-1)=0 are s=9,s=1
Find the zeros of (s-9)(s-1)=0
The zeros of (s-9)(s-1)=0 are s=9,s=1