What is 1/2 ln(4.1931i) ?

The solution to 1/2 ln(4.1931i) is 1/2 ln(4.1931)+1/2 ln(i)

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simplify 1/2 ln(4.1931i)

simplify

\frac{1}{2} ln (4.1931 i)

\frac{1}{2} ln (4.1931) + \frac{1}{2} ln (i)

Solution steps

\frac{1}{2} ln (4.1931 i)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

\frac{1}{2} ln (4.1931 i) = \frac{1}{2} ln (4.1931) + \frac{1}{2} ln (i)

= \frac{1}{2} ln (4.1931) + \frac{1}{2} ln (i)

- lo g_{10} (6.5 \cdot 1 0^{- 9})

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- ln (x + 1) + ln (x^{\frac{1}{2}})

- \frac{2 ln ( 12 )}{ln ( 10 )}

What is 1/2 ln(4.1931i) ?
The solution to 1/2 ln(4.1931i) is 1/2 ln(4.1931)+1/2 ln(i)