What is log_{2}(49.92)-log_{2}(6.24) ?

The solution to log_{2}(49.92)-log_{2}(6.24) is 3

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simplify log_{2}(49.92)-log_{2}(6.24)

simplify

lo g_{2} (49.92) - lo g_{2} (6.24)

3

Solution steps

lo g_{2} (49.92) - lo g_{2} (6.24)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{2} (49.92) - lo g_{2} (6.24) = lo g_{2} (\frac{49.92}{6.24})

= lo g_{2} (\frac{49.92}{6.24})

\frac{49.92}{6.24} = 8

= lo g_{2} (8)

Factor the number:

8 = 2^{3}

= lo g_{2} (2^{3})

Apply log rule:

lo g_{a} (a^{b}) = b

= 3

ln (\frac{x}{e ^{7 x}})

\frac{19 ln ( \frac{8}{33} )}{9}

ln (\frac{54}{60})

ln (\frac{x + 1}{x + 3})

ln (\frac{x - y}{y}) - ln (y)

What is log_{2}(49.92)-log_{2}(6.24) ?
The solution to log_{2}(49.92)-log_{2}(6.24) is 3