What are the solutions to the equation 5x^2-10x+5=0 ?

The solutions to the equation 5x^2-10x+5=0 are x=1

Find the zeros of 5x^2-10x+5=0

The zeros of 5x^2-10x+5=0 are x=1

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5 x^{2} - 10 x + 5 = 0

x = 1

Solution steps

5 x^{2} - 10 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

(- 10)^{2} - 4 \cdot 5 \cdot 5 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 5}

x = \frac{- ( - 10 )}{2 \cdot 5}

\frac{- ( - 10 )}{2 \cdot 5} = 1

x = 1

The solution to the quadratic equation is:

x = 1

3 + 2 n > 9

n^{2} + 12 n + 27

(k^{2})^{4}

- 3 x^{2} - x + 4

\frac{π}{12} - \frac{π}{2}

What are the solutions to the equation 5x^2-10x+5=0 ?
The solutions to the equation 5x^2-10x+5=0 are x=1
Find the zeros of 5x^2-10x+5=0
The zeros of 5x^2-10x+5=0 are x=1