What is ln(z^2+3)-ln(z^2-4) ?

The solution to ln(z^2+3)-ln(z^2-4) is ln((z^2+3)/(z^2-4))

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simplify ln(z^2+3)-ln(z^2-4)

simplify

ln (z^{2} + 3) - ln (z^{2} - 4)

ln (\frac{z ^{2} + 3}{z ^{2} - 4})

Solution steps

ln (z^{2} + 3) - ln (z^{2} - 4)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (z^{2} + 3) - ln (z^{2} - 4) = ln (\frac{z ^{2} + 3}{z ^{2} - 4})

= ln (\frac{z ^{2} + 3}{z ^{2} - 4})

ln (\frac{10000}{2780.7})

\frac{1}{2} ln (x) + 3 ln (x - 1)

ln (e^{x}) + 3 ln (x) + 4 ln (x + 1)

ln (2 + x) - ln (1 + x)

5 ln (θ) + 5 ln (1 - θ)

What is ln(z^2+3)-ln(z^2-4) ?
The solution to ln(z^2+3)-ln(z^2-4) is ln((z^2+3)/(z^2-4))