What is ln((1+y^2)/(x^2+xy)) ?

The solution to ln((1+y^2)/(x^2+xy)) is ln(1+y^2)-ln(x^2+xy)

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simplify ln((1+y^2)/(x^2+xy))

simplify

ln (\frac{1 + y ^{2}}{x ^{2} + x y})

ln (1 + y^{2}) - ln (x^{2} + x y)

Solution steps

ln (\frac{1 + y ^{2}}{x ^{2} + x y})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1 + y ^{2}}{x ^{2} + x y}) = ln (1 + y^{2}) - ln (x^{2} + x y)

= ln (y^{2} + 1) - ln (x^{2} + y x)

ln (\frac{e}{10})

\frac{1}{3} ln (\frac{80}{100})

ln (c - 1) - ln (c)

ln (\frac{x \cdot y}{e ^{1}})

- 3 lo g_{ba} (b) - 3 lo g_{ba} (a)

What is ln((1+y^2)/(x^2+xy)) ?
The solution to ln((1+y^2)/(x^2+xy)) is ln(1+y^2)-ln(x^2+xy)