What is log_{10}((-1)/a) ?

The solution to log_{10}((-1)/a) is log_{10}(-1)-log_{10}(a)

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simplify log_{10}((-1)/a)

simplify

lo g_{10} (\frac{- 1}{a})

lo g_{10} (- 1) - lo g_{10} (a)

Solution steps

lo g_{10} (\frac{- 1}{a})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{- 1}{a}) = lo g_{10} (- 1) - lo g_{10} (a)

= lo g_{10} (- 1) - lo g_{10} (a)

ln (\frac{4 + 3 x}{4 + x})

ln (3^{1 + x} \cdot 2^{x})

ln (\frac{ab}{c})

ln (c x^{n})

ln (\frac{1}{2 ^{\frac{3}{4}}})

What is log_{10}((-1)/a) ?
The solution to log_{10}((-1)/a) is log_{10}(-1)-log_{10}(a)