What is expand ln((0.46+5.34i)^{1.5e^{1.1}}) ?

The solution to expand ln((0.46+5.34i)^{1.5e^{1.1}}) is 1.5e^{1.1}ln(0.46+5.34i)

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expand ln((0.46+5.34i)^{1.5e^{1.1}})

expand

ln ((0.46 + 5.34 i)^{1.5 e^{1.1}})

1.5 e^{1.1} ln (0.46 + 5.34 i)

Solution steps

ln ((0.46 + 5.34 i)^{1.5 e^{1.1}})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln ((0.46 + 5.34 i)^{1.5 e^{1.1}}) = 1.5 e^{1.1} ln (0.46 + 5.34 i)

= 1.5 e^{1.1} ln (0.46 + 5.34 i)

ln (\frac{15}{400})

ln (\frac{17}{5})

- ln (- b (ln (a)))

\frac{3}{5} ln (x) - 7 ln (y)

- 5 + ln (\frac{29}{4})

What is expand ln((0.46+5.34i)^{1.5e^{1.1}}) ?
The solution to expand ln((0.46+5.34i)^{1.5e^{1.1}}) is 1.5e^{1.1}ln(0.46+5.34i)