What is e^x+log_{10}(2x^2) ?

The solution to e^x+log_{10}(2x^2) is e^x+log_{10}(2)+2log_{10}(x)

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simplify e^x+log_{10}(2x^2)

simplify

e^{x} + lo g_{10} (2 x^{2})

e^{x} + lo g_{10} (2) + 2 lo g_{10} (x)

Solution steps

e^{x} + lo g_{10} (2 x^{2})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (2 x^{2}) = lo g_{10} (2) + lo g_{10} (x^{2})

= e^{x} + lo g_{10} (2) + lo g_{10} (x^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (x^{2}) = 2 lo g_{10} (x)

= e^{x} + lo g_{10} (2) + 2 lo g_{10} (x)

4.76 + lo g_{10} (\frac{0.8}{3})

3 ln (216) + 4 ln (\frac{1}{36})

\frac{1.6}{2} ln (10) - 1.6 ln (3)

2 ln (a) - ln (a^{2} + 1)

ln ((x^{2} + 4) (x - 4))

What is e^x+log_{10}(2x^2) ?
The solution to e^x+log_{10}(2x^2) is e^x+log_{10}(2)+2log_{10}(x)