What is x^4-ln(xy)+3^{2x+y^2} ?

The solution to x^4-ln(xy)+3^{2x+y^2} is x^4-ln(x)-ln(y)+3^{2x+y^2}

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simplify x^4-ln(xy)+3^{2x+y^2}

simplify

x^{4} - ln (x y) + 3^{2 x + y^{2}}

x^{4} - ln (x) - ln (y) + 3^{2 x + y^{2}}

Solution steps

x^{4} - ln (x y) + 3^{2 x + y^{2}}

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (x y) = ln (x) + ln (y)

= x^{4} - (ln (x) + ln (y)) + 3^{2 x + y^{2}}

- (ln (x) + ln (y)) : - ln (x) - ln (y)

= x^{4} - ln (x) - ln (y) + 3^{2 x + y^{2}}

lo g_{4} (n) + 3 lo g_{4} (m)

- lo g_{10} (8.2 \cdot 1 0^{- 5})

- ln (\frac{2}{cos ( x )})

lo g_{10} (6 x^{4})

ln (4 x) + ln (3 x)

What is x^4-ln(xy)+3^{2x+y^2} ?
The solution to x^4-ln(xy)+3^{2x+y^2} is x^4-ln(x)-ln(y)+3^{2x+y^2}