What are the solutions to the equation s^2+52s+238=0 ?

The solutions to the equation s^2+52s+238=0 are s=-26+sqrt(438),s=-26-sqrt(438)

Find the zeros of s^2+52s+238=0

The zeros of s^2+52s+238=0 are s=-26+sqrt(438),s=-26-sqrt(438)

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s^{2} + 52 s + 238 = 0

s = - 26 + 438, s = - 26 - 438

Decimal Notation

s = - 5.07155 \dots, s = - 46.92844 \dots

Solution steps

s^{2} + 52 s + 238 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 52 \pm 5 2 ^{2} - 4 \cdot 1 \cdot 238}{2 \cdot 1}

5 2^{2} - 4 \cdot 1 \cdot 238 = 2438

s_{1, 2} = \frac{- 52 \pm 2 438}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 52 + 2 438}{2 \cdot 1}, s_{2} = \frac{- 52 - 2 438}{2 \cdot 1}

s = \frac{- 52 + 2 438}{2 \cdot 1} : - 26 + 438

s = \frac{- 52 - 2 438}{2 \cdot 1} : - 26 - 438

The solutions to the quadratic equation are:

s = - 26 + 438, s = - 26 - 438

- x^{2} - 2 x + 4 = 0

a^{m} \cdot a^{n}

(7^{3})^{3}

(3 + 2) (3 + 2)

8 q - 3 < 10 q + 7

What are the solutions to the equation s^2+52s+238=0 ?
The solutions to the equation s^2+52s+238=0 are s=-26+sqrt(438),s=-26-sqrt(438)
Find the zeros of s^2+52s+238=0
The zeros of s^2+52s+238=0 are s=-26+sqrt(438),s=-26-sqrt(438)