What is 4log_{a}(k)-3log_{a}(m) ?

The solution to 4log_{a}(k)-3log_{a}(m) is log_{a}((k^4)/(m^3))

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simplify 4log_{a}(k)-3log_{a}(m)

simplify

4 lo g_{a} (k) - 3 lo g_{a} (m)

lo g_{a} (\frac{k ^{4}}{m ^{3}})

Solution steps

4 lo g_{a} (k) - 3 lo g_{a} (m)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{a} (k) = lo g_{a} (k^{4})

= lo g_{a} (k^{4}) - 3 lo g_{a} (m)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{a} (m) = lo g_{a} (m^{3})

= lo g_{a} (k^{4}) - lo g_{a} (m^{3})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{a} (k^{4}) - lo g_{a} (m^{3}) = lo g_{a} (\frac{k ^{4}}{m ^{3}})

= lo g_{a} (\frac{k ^{4}}{m ^{3}})

- lo g_{10} (8.32 \cdot 1 0^{- 9})

2 ln (x e^{x})

6 ln (6) - 5 ln (5)

lo g_{10} (45) + lo g_{10} (2.5)

x (ln (4) - ln (5))

What is 4log_{a}(k)-3log_{a}(m) ?
The solution to 4log_{a}(k)-3log_{a}(m) is log_{a}((k^4)/(m^3))