What is join 1/3 log_{10}(245) ?

The solution to join 1/3 log_{10}(245) is log_{10}(245^{1/3})

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join 1/3 log_{10}(245)

join

\frac{1}{3} lo g_{10} (245)

lo g_{10} (24 5^{\frac{1}{3}})

Solution steps

\frac{1}{3} lo g_{10} (245)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{1}{3} lo g_{10} (245) = lo g_{10} (24 5^{\frac{1}{3}})

= lo g_{10} (24 5^{\frac{1}{3}})

6 lo g_{b} (m) - 5 lo g_{b} (n) + 3

ln (y) + ln (y + 1)

ln (1 + e^{2 x}) - ln (2)

ln (100 \cdot (1 + r)^{60})

ln (y^{3}) - ln (y) - ln (y^{6})

What is join 1/3 log_{10}(245) ?
The solution to join 1/3 log_{10}(245) is log_{10}(245^{1/3})