What is ln(2x+6)-ln(7x^2+3) ?

The solution to ln(2x+6)-ln(7x^2+3) is ln((2x+6)/(7x^2+3))

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simplify ln(2x+6)-ln(7x^2+3)

simplify

ln (2 x + 6) - ln (7 x^{2} + 3)

ln (\frac{2 x + 6}{7 x ^{2} + 3})

Solution steps

ln (2 x + 6) - ln (7 x^{2} + 3)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (2 x + 6) - ln (7 x^{2} + 3) = ln (\frac{2 x + 6}{7 x ^{2} + 3})

= ln (\frac{2 x + 6}{7 x ^{2} + 3})

ln (x (x + 4) (x + 8))

ln (v e^{- \frac{t}{rc}})

ln ((x) ln (y))

ln (r^{9} s^{53} r 5 s^{2})

0.000003 ln (\frac{100}{5200})

What is ln(2x+6)-ln(7x^2+3) ?
The solution to ln(2x+6)-ln(7x^2+3) is ln((2x+6)/(7x^2+3))