What is simplify-ln(e^x+1)+ln(2) ?

The solution to simplify-ln(e^x+1)+ln(2) is ln(2/(e^x+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify-ln(e^x+1)+ln(2)

simplify

- ln (e^{x} + 1) + ln (2)

ln (\frac{2}{e ^{x} + 1})

Solution steps

- ln (e^{x} + 1) + ln (2)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (2) - ln (e^{x} + 1) = ln (\frac{2}{e ^{x} + 1})

= ln (\frac{2}{e ^{x} + 1})

2 ln (\frac{x - 1}{x + 2})

lo g_{10} (z^{6})

lo g_{2} (3 t) + lo g_{2} (5 t)

- lo g_{10} (5.5 \cdot 1 0^{- 11})

- lo g_{10} (6.324 \cdot 1 0^{- 6})

What is simplify-ln(e^x+1)+ln(2) ?
The solution to simplify-ln(e^x+1)+ln(2) is ln(2/(e^x+1))