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Popular >

simplify ln(e^{(-e/(Rt))}t)

Solution

simplify

ln (e^{(- \frac{e}{Rt})} t)

Solution

- \frac{e}{Rt} + ln (t)

Solution steps

ln (e^{(- \frac{e}{Rt})} t)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (e^{(- \frac{e}{Rt})} t) = ln (e^{(- \frac{e}{Rt})}) + ln (t)

= ln (e^{(- \frac{e}{Rt})}) + ln (t)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (e^{(- \frac{e}{Rt})}) = (- \frac{e}{Rt}) ln (e)

= (- \frac{e}{Rt}) ln (e) + ln (t)

Remove parentheses:

(- a) = - a

= - \frac{e}{Rt} ln (e) + ln (t)

\frac{e}{Rt} ln (e) = \frac{e}{Rt}

= - \frac{e}{Rt} + ln (t)

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Frequently Asked Questions (FAQ)

What is ln(e^{(-e/(Rt))}t) ?
The solution to ln(e^{(-e/(Rt))}t) is -e/(Rt)+ln(t)