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Popular >

simplify ln(-e^{-y}(y+1))

Solution

simplify

ln (- e^{- y} (y + 1))

Solution

- y + ln (y + 1)

Solution steps

ln (- e^{- y} (y + 1))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (- e^{- y} (y + 1)) = ln (e^{- y}) + ln (y + 1)

= ln (e^{- y}) + ln (y + 1)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (e^{- y}) = - y ln (e)

= - y ln (e) + ln (y + 1)

y ln (e) = y

= - y + ln (y + 1)

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Frequently Asked Questions (FAQ)

What is ln(-e^{-y}(y+1)) ?
The solution to ln(-e^{-y}(y+1)) is -y+ln(y+1)