What are the solutions to the equation z^2-4z+5=0 ?

The solutions to the equation z^2-4z+5=0 are z=2+i,z=2-i

Find the zeros of z^2-4z+5=0

The zeros of z^2-4z+5=0 are z=2+i,z=2-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

z^{2} - 4 z + 5 = 0

z = 2 + i, z = 2 - i

Solution steps

z^{2} - 4 z + 5 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 5 : 2 i

z_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 4 ) + 2 i}{2 \cdot 1}, z_{2} = \frac{- ( - 4 ) - 2 i}{2 \cdot 1}

z = \frac{- ( - 4 ) + 2 i}{2 \cdot 1} : 2 + i

z = \frac{- ( - 4 ) - 2 i}{2 \cdot 1} : 2 - i

The solutions to the quadratic equation are:

z = 2 + i, z = 2 - i

11 x + 4 < 15 or 12 x - 7 > - 25

\frac{8 !}{( 8 - 4 ) ! 4 !}

\frac{1}{2} \cdot 6 \cdot 5

2 x + 1 \leq - 4 or 2 x + 1 \geq 4

- 2 y - 5 \leq 19

What are the solutions to the equation z^2-4z+5=0 ?
The solutions to the equation z^2-4z+5=0 are z=2+i,z=2-i
Find the zeros of z^2-4z+5=0
The zeros of z^2-4z+5=0 are z=2+i,z=2-i