What is join 1/5 ln(e^{5x}+c) ?

The solution to join 1/5 ln(e^{5x}+c) is ln((e^{5x}+c)^{1/5})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

join 1/5 ln(e^{5x}+c)

join

\frac{1}{5} ln (e^{5 x} + c)

ln ((e^{5 x} + c)^{\frac{1}{5}})

Solution steps

\frac{1}{5} ln (e^{5 x} + c)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{1}{5} ln (e^{5 x} + c) = ln ((e^{5 x} + c)^{\frac{1}{5}})

= ln ((e^{5 x} + c)^{\frac{1}{5}})

ln (\frac{2}{0.0035})

lo g_{e} (x + 2) - lo g_{e} (3 x)

ln ((x^{2} + 8 x + 7) (2 x^{2} - 16 x))

ln (\frac{15}{13 - 2 ( 1.5 )})

ln^{5} (\frac{( e ^{2} )}{5})

What is join 1/5 ln(e^{5x}+c) ?
The solution to join 1/5 ln(e^{5x}+c) is ln((e^{5x}+c)^{1/5})