What is expand ln((-3.5+0.75x)e^{-0,5x}) ?

The solution to expand ln((-3.5+0.75x)e^{-0,5x}) is ln(-3.5+0.75x)-0,5xln(e)

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expand ln((-3.5+0.75x)e^{-0,5x})

expand

ln ((- 3.5 + 0.75 x) e^{- 0, 5 x})

ln (- 3.5 + 0.75 x) - 0, 5 x ln (e)

Solution steps

ln ((- 3.5 + 0.75 x) e^{- 0, 5 x})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln ((- 3.5 + 0.75 x) e^{- 0, 5 x}) = ln (- 3.5 + 0.75 x) + ln (e^{- 0, 5 x})

= ln (0.75 x - 3.5) + ln (e^{- 0 \cdot 5, x})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (e^{- 0, 5 x}) = - 0, 5 x ln (e)

= ln (- 3.5 + 0.75 x) - 0, 5 x ln (e)

lo g_{4} (\frac{17}{3})

ln (E) - ln (D)

ln (x) + ln (ln (x))

ln (y e^{y})

\frac{3 ln ( 2 )}{ln ( 3 )} - 1

What is expand ln((-3.5+0.75x)e^{-0,5x}) ?
The solution to expand ln((-3.5+0.75x)e^{-0,5x}) is ln(-3.5+0.75x)-0,5xln(e)