What are the solutions to the equation (x-1)^2-5=3 ?

The solutions to the equation (x-1)^2-5=3 are x=2sqrt(2)+1,x=-2sqrt(2)+1

Find the zeros of (x-1)^2-5=3

The zeros of (x-1)^2-5=3 are x=2sqrt(2)+1,x=-2sqrt(2)+1

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(x - 1)^{2} - 5 = 3

x = 22 + 1, x = - 22 + 1

Decimal Notation

x = 3.82842 \dots, x = - 1.82842 \dots

Solution steps

(x - 1)^{2} - 5 = 3

Move

5

to the right side

(x - 1)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 8 : x = 22 + 1

Solve

x - 1 = - 8 : x = - 22 + 1

The solutions to the quadratic equation are:

x = 22 + 1, x = - 22 + 1

(4^{\frac{1}{2}})^{\frac{2}{3}}

- x \leq 9

20 x^{2} + 1 = x

(- 8) \frac{4}{3}

What are the solutions to the equation (x-1)^2-5=3 ?
The solutions to the equation (x-1)^2-5=3 are x=2sqrt(2)+1,x=-2sqrt(2)+1
Find the zeros of (x-1)^2-5=3
The zeros of (x-1)^2-5=3 are x=2sqrt(2)+1,x=-2sqrt(2)+1