What is ln((e^{-y}+1)(1+cos(x)))+y ?

The solution to ln((e^{-y}+1)(1+cos(x)))+y is ln(e^{-y}+1)+ln(1+cos(x))+y

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simplify ln((e^{-y}+1)(1+cos(x)))+y

simplify

ln ((e^{- y} + 1) (1 + cos (x))) + y

ln (e^{- y} + 1) + ln (1 + cos (x)) + y

Solution steps

ln ((e^{- y} + 1) (1 + cos (x))) + y

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln ((e^{- y} + 1) (1 + cos (x))) = ln (e^{- y} + 1) + ln (1 + cos (x))

= ln (e^{- y} + 1) + ln (cos (x) + 1) + y

ln (2 i^{8 i})

ln (e^{3} + e^{- 3}) - ln (2)

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2 + 2 ln (5 x)

ln^{2} (3 e) - 3 ln (3) - 3

What is ln((e^{-y}+1)(1+cos(x)))+y ?
The solution to ln((e^{-y}+1)(1+cos(x)))+y is ln(e^{-y}+1)+ln(1+cos(x))+y