What is ln(7x^3-9)-ln(2x^2+7) ?

The solution to ln(7x^3-9)-ln(2x^2+7) is ln((7x^3-9)/(2x^2+7))

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simplify ln(7x^3-9)-ln(2x^2+7)

simplify

ln (7 x^{3} - 9) - ln (2 x^{2} + 7)

ln (\frac{7 x ^{3} - 9}{2 x ^{2} + 7})

Solution steps

ln (7 x^{3} - 9) - ln (2 x^{2} + 7)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (7 x^{3} - 9) - ln (2 x^{2} + 7) = ln (\frac{7 x ^{3} - 9}{2 x ^{2} + 7})

= ln (\frac{7 x ^{3} - 9}{2 x ^{2} + 7})

ln (\frac{5000000}{3200000})

ln^{\frac{5}{7}} (\frac{1}{2})

ln (\frac{283}{273})

ln (\frac{0.01}{1 - 0.01})

ln (80 (60)^{n})

What is ln(7x^3-9)-ln(2x^2+7) ?
The solution to ln(7x^3-9)-ln(2x^2+7) is ln((7x^3-9)/(2x^2+7))