What is ln_{2}(x+2)-ln_{2}(x+1) ?

The solution to ln_{2}(x+2)-ln_{2}(x+1) is ln_{2}((x+2)/(x+1))

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simplify ln_{2}(x+2)-ln_{2}(x+1)

simplify

ln_{2} (x + 2) - ln_{2} (x + 1)

ln_{2} (\frac{x + 2}{x + 1})

Solution steps

ln_{2} (x + 2) - ln_{2} (x + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln_{2} (x + 2) - ln_{2} (x + 1) = ln_{2} (\frac{x + 2}{x + 1})

= ln_{2} (\frac{x + 2}{x + 1})

ln (\frac{y}{e ^{2}})

lo g_{10} (y) - 2 lo g_{10} (y - 1)

ln (\frac{( 3 x - 5 ) ^{2}}{7})

20 ln (3 x)

\frac{1}{2} ln (\frac{40}{50})

What is ln_{2}(x+2)-ln_{2}(x+1) ?
The solution to ln_{2}(x+2)-ln_{2}(x+1) is ln_{2}((x+2)/(x+1))