What is log_{10}(a)-2log_{10}(b)+3 ?

The solution to log_{10}(a)-2log_{10}(b)+3 is log_{10}(a/(b^2))+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}(a)-2log_{10}(b)+3

simplify

lo g_{10} (a) - 2 lo g_{10} (b) + 3

lo g_{10} (\frac{a}{b ^{2}}) + 3

Solution steps

lo g_{10} (a) - 2 lo g_{10} (b) + 3

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (b) = lo g_{10} (b^{2})

= lo g_{10} (a) - lo g_{10} (b^{2}) + 3

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (a) - lo g_{10} (b^{2}) = lo g_{10} (\frac{a}{b ^{2}})

= lo g_{10} (\frac{a}{b ^{2}}) + 3

ln (16) + ln (7) - 3 ln (2)

6.1 + lo g_{10} (\frac{B}{C})

lo g_{2} (\frac{( 4 π ^{2} )}{30})

4 + 2 ln (2) - 2 + 2 ln (x)

x - lo g_{e} (x) - lo g_{e} (0.17)

What is log_{10}(a)-2log_{10}(b)+3 ?
The solution to log_{10}(a)-2log_{10}(b)+3 is log_{10}(a/(b^2))+3