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Popular >

simplify ln(t)+ln(sin(2^t))

Solution

simplify

ln (t) + ln (sin (2^{t}))

Solution

ln (t sin (2^{t}))

Solution steps

ln (t) + ln (sin (2^{t}))

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (t) + ln (sin (2^{t})) = ln (t sin (2^{t}))

= ln (t sin (2^{t}))

Popular Examples

simplify-log_{10}(3.3*10^{-5})simplify

- lo g_{10} (3.3 \cdot 1 0^{- 5})

simplify ln(x+1)-ln(2)simplify

ln (x + 1) - ln (2)

simplify-log_{10}(2.84*10^{-3})simplify

- lo g_{10} (2.84 \cdot 1 0^{- 3})

simplify 2log_{10}(x)-5log_{10}(x+8)simplify

2 lo g_{10} (x) - 5 lo g_{10} (x + 8)

simplify-2(ln(80)-ln(100))simplify

- 2 (ln (80) - ln (100))

Frequently Asked Questions (FAQ)

What is ln(t)+ln(sin(2^t)) ?
The solution to ln(t)+ln(sin(2^t)) is ln(tsin(2^t))