What are the solutions to the equation -d^2-12d+4=-6d^2 ?

The solutions to the equation -d^2-12d+4=-6d^2 are d=2,d= 2/5

Find the zeros of -d^2-12d+4=-6d^2

The zeros of -d^2-12d+4=-6d^2 are d=2,d= 2/5

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- d^{2} - 12 d + 4 = - 6 d^{2}

d = 2, d = \frac{2}{5}

Solution steps

- d^{2} - 12 d + 4 = - 6 d^{2}

Move

6 d^{2}

to the left side

5 d^{2} - 12 d + 4 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 \cdot 4 = 8

d_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 5}

Separate the solutions

d_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 5}, d_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 5}

d = \frac{- ( - 12 ) + 8}{2 \cdot 5} : 2

d = \frac{- ( - 12 ) - 8}{2 \cdot 5} : \frac{2}{5}

The solutions to the quadratic equation are:

d = 2, d = \frac{2}{5}

8 \cdot 20

20 \cdot 10

(32)^{\frac{3}{5}}

\frac{- 9 - 6 i}{- 3 - 2 i}

\frac{1}{15} \cdot \frac{6}{11}

What are the solutions to the equation -d^2-12d+4=-6d^2 ?
The solutions to the equation -d^2-12d+4=-6d^2 are d=2,d= 2/5
Find the zeros of -d^2-12d+4=-6d^2
The zeros of -d^2-12d+4=-6d^2 are d=2,d= 2/5