What is expand ln((4x+1)^{cot(x)}) ?

The solution to expand ln((4x+1)^{cot(x)}) is cot(x)ln(4x+1)

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expand ln((4x+1)^{cot(x)})

expand

ln ((4 x + 1)^{c o t (x)})

cot (x) ln (4 x + 1)

Solution steps

ln ((4 x + 1)^{c o t (x)})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln ((4 x + 1)^{c o t (x)}) = cot (x) ln (4 x + 1)

= cot (x) ln (4 x + 1)

ln (v - 1) - ln (v + 1)

- lo g_{10} (1.77 \cdot 1 0^{- 4})

ln (\frac{1}{( x - 3 )})

\frac{1}{4} (ln (1297) - ln (2))

ln (θ x^{- 2})

What is expand ln((4x+1)^{cot(x)}) ?
The solution to expand ln((4x+1)^{cot(x)}) is cot(x)ln(4x+1)