What is ln(2w+2)-ln(k)-ln(b) ?

The solution to ln(2w+2)-ln(k)-ln(b) is ln((2w+2)/(bk))

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simplify ln(2w+2)-ln(k)-ln(b)

simplify

ln (2 w + 2) - ln (k) - ln (b)

ln (\frac{2 w + 2}{bk})

Solution steps

ln (2 w + 2) - ln (k) - ln (b)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (2 w + 2) - ln (k) = ln (\frac{2 w + 2}{k})

= ln (\frac{2 w + 2}{k}) - ln (b)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (\frac{2 w + 2}{k}) - ln (b) = ln (\frac{\frac{2 w + 2}{k}}{b})

= ln (\frac{\frac{2 w + 2}{k}}{b})

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= ln (\frac{2 w + 2}{bk})

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What is ln(2w+2)-ln(k)-ln(b) ?
The solution to ln(2w+2)-ln(k)-ln(b) is ln((2w+2)/(bk))