What is 5e^3+2ln(3+2)+1-5e-2ln(3) ?

The solution to 5e^3+2ln(3+2)+1-5e-2ln(3) is 5e^3+ln(25/9)+1-5e

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simplify 5e^3+2ln(3+2)+1-5e-2ln(3)

simplify

5 e^{3} + 2 ln (3 + 2) + 1 - 5 e - 2 ln (3)

5 e^{3} + ln (\frac{25}{9}) + 1 - 5 e

Decimal Notation

88.85792 \dots

Solution steps

5 e^{3} + 2 ln (3 + 2) + 1 - 5 e - 2 ln (3)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (3 + 2) = ln ((3 + 2)^{2})

= 5 e^{3} + ln ((3 + 2)^{2}) + 1 - 5 e - 2 ln (3)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (3) = ln (3^{2})

= 5 e^{3} + ln ((3 + 2)^{2}) + 1 - 5 e - ln (3^{2})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ((3 + 2)^{2}) - ln (3^{2}) = ln (\frac{( 3 + 2 ) ^{2}}{3 ^{2}})

= 5 e^{3} + ln (\frac{( 3 + 2 ) ^{2}}{3 ^{2}}) + 1 - 5 e

\frac{( 3 + 2 ) ^{2}}{3 ^{2}} = \frac{25}{9}

= 5 e^{3} + ln (\frac{25}{9}) + 1 - 5 e

(1 \cdot 5) ln (\frac{5}{1})

- lo g_{10} (3.56 \cdot 1 0^{- 3})

- lo g_{10} (8.3 \cdot 1 0^{- 7})

ln (\frac{2}{1 - x - y})

\frac{ln ( 2 ) - ln ( 3 )}{5}

What is 5e^3+2ln(3+2)+1-5e-2ln(3) ?
The solution to 5e^3+2ln(3+2)+1-5e-2ln(3) is 5e^3+ln(25/9)+1-5e