What are the solutions to the equation 3y^2=48 ?

The solutions to the equation 3y^2=48 are y=4,y=-4

Find the zeros of 3y^2=48

The zeros of 3y^2=48 are y=4,y=-4

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3 y^{2} = 48

y = 4, y = - 4

Solution steps

3 y^{2} = 48

Divide both sides by

3

y^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 16, y = - 16

16 = 4

- 16 = - 4

y = 4, y = - 4

8 z - 1 = 11

\frac{x}{12} + 6 = 8

3 y^{3} + 5 y^{2} + 3 y + 5

24 x y^{2} + 40 y

3 \cdot 3

What are the solutions to the equation 3y^2=48 ?
The solutions to the equation 3y^2=48 are y=4,y=-4
Find the zeros of 3y^2=48
The zeros of 3y^2=48 are y=4,y=-4