What is 2sin(npi)-sin(2npi) ?

The solution to 2sin(npi)-sin(2npi) is -sin(2pin)

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simplify 2sin(npi)-sin(2npi)

simplify

2 sin (nπ) - sin (2 nπ)

- sin (2 πn)

Solution steps

2 sin (nπ) - sin (2 nπ)

Use the basic trigonometric identity:

sin (nπ) = 0

= - sin (2 nπ) + 2 \cdot 0

Refine

= - sin (2 πn)

sec (arccos (x))

tan (arccos (3 x))

sin (12 0^{\circ} - x)

cos (2 x - \frac{π}{2})

cos (x + 2 π)