What is 1+tan^2(90-θ) ?

The solution to 1+tan^2(90-θ) is csc^2(θ)

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simplify 1+tan^2(90-θ)

simplify

1 + tan^{2} (9 0^{\circ} - θ)

csc^{2} (θ)

Solution steps

1 + tan^{2} (9 0^{\circ} - θ)

Rewrite using trig identities

= 1 + (\frac{cos ( θ )}{sin ( θ )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= 1 + \frac{cos ^{2} ( θ )}{sin ^{2} ( θ )}

Rewrite using trig identities

= csc^{2} (θ)

sin (\frac{5 π}{2} + 2 α)

1 - cos (2 x)

tan (θ + π)

cos (arcsin (\frac{x - h}{r}))

sin (arcsec (\frac{x}{2}))