What are the solutions to the equation -2x^2+x=0 ?

The solutions to the equation -2x^2+x=0 are x=0,x= 1/2

Find the zeros of -2x^2+x=0

The zeros of -2x^2+x=0 are x=0,x= 1/2

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- 2 x^{2} + x = 0

x = 0, x = \frac{1}{2}

Decimal Notation

x = 0, x = 0.5

Solution steps

- 2 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 2 )}, x_{2} = \frac{- 1 - 1}{2 ( - 2 )}

x = \frac{- 1 + 1}{2 ( - 2 )} : 0

x = \frac{- 1 - 1}{2 ( - 2 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{2}

8.5 \cdot 1 0^{- 3} = \frac{x \cdot x}{( 2.3 \cdot 1 0 ^{- 2} ) ^{2}}

f a t^{48} x^{2} + 36 x

14 x + 23 = 14 x - 23

520 = - 16 t^{2} + 108 t + 520

5 X - 12 > 3 X - 4

What are the solutions to the equation -2x^2+x=0 ?
The solutions to the equation -2x^2+x=0 are x=0,x= 1/2
Find the zeros of -2x^2+x=0
The zeros of -2x^2+x=0 are x=0,x= 1/2