What are the solutions to the equation 3w^2-12w+7=0 ?

The solutions to the equation 3w^2-12w+7=0 are w=(6+sqrt(15))/3 ,w=(6-sqrt(15))/3

Find the zeros of 3w^2-12w+7=0

The zeros of 3w^2-12w+7=0 are w=(6+sqrt(15))/3 ,w=(6-sqrt(15))/3

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3 w^{2} - 12 w + 7 = 0

w = \frac{6 + 15}{3}, w = \frac{6 - 15}{3}

Decimal Notation

w = 3.29099 \dots, w = 0.70900 \dots

Solution steps

3 w^{2} - 12 w + 7 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 7 = 215

w_{1, 2} = \frac{- ( - 12 ) \pm 2 15}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- ( - 12 ) + 2 15}{2 \cdot 3}, w_{2} = \frac{- ( - 12 ) - 2 15}{2 \cdot 3}

w = \frac{- ( - 12 ) + 2 15}{2 \cdot 3} : \frac{6 + 15}{3}

w = \frac{- ( - 12 ) - 2 15}{2 \cdot 3} : \frac{6 - 15}{3}

The solutions to the quadratic equation are:

w = \frac{6 + 15}{3}, w = \frac{6 - 15}{3}

3 x^{2} - 9 - 18

5 (4 - 5) 2 + 3 (5 - 1) - 2 (1 + 2) 2 (2) + 2 (3) (4)

- 4 \leq x \leq 3

∣ y ∣ + 18 \leq 8

\frac{( 2320 ) ^{4}}{( 830 ) ^{4}}

What are the solutions to the equation 3w^2-12w+7=0 ?
The solutions to the equation 3w^2-12w+7=0 are w=(6+sqrt(15))/3 ,w=(6-sqrt(15))/3
Find the zeros of 3w^2-12w+7=0
The zeros of 3w^2-12w+7=0 are w=(6+sqrt(15))/3 ,w=(6-sqrt(15))/3