What is sqrt(4-4sin^2(θ)) ?

The solution to sqrt(4-4sin^2(θ)) is 2sqrt(cos^2(θ))

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simplify sqrt(4-4sin^2(θ))

simplify

4 - 4 sin^{2} (θ)

2 cos^{2} (θ)

Solution steps

4 - 4 sin^{2} (θ)

Factor

4 - 4 sin^{2} (θ) : 4 (1 - sin^{2} (θ))

= 4 (1 - sin^{2} (θ))

Apply radical rule:

assuming

a \geq 0, b \geq 0

= 4 - sin^{2} (θ) + 1

4 = 2

= 2 - sin^{2} (θ) + 1

Rewrite using trig identities

= 2 cos^{2} (θ)

sin (π \cdot n)

6 sin^{3} (2 x + \frac{π}{3})

cos (arcsin (a x))

- 2 cos (3 x - \frac{π}{2})

- cot (18 0^{\circ} - x)

What is sqrt(4-4sin^2(θ)) ?
The solution to sqrt(4-4sin^2(θ)) is 2sqrt(cos^2(θ))