What are the solutions to the equation x^2+12^2=15^2 ?

The solutions to the equation x^2+12^2=15^2 are x=9,x=-9

Find the zeros of x^2+12^2=15^2

The zeros of x^2+12^2=15^2 are x=9,x=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 1 2^{2} = 1 5^{2}

x = 9, x = - 9

Solution steps

x^{2} + 1 2^{2} = 1 5^{2}

Move

1 2^{2}

to the right side

x^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

\frac{6}{9} \cdot 15

\frac{2 !}{( 2 - 2 ) ! \cdot 2 !}

2 - 4 (\frac{2 x}{7} + \frac{1}{7}) = \frac{3}{2} - x

4 + y = 6

27 y^{3} - 1

What are the solutions to the equation x^2+12^2=15^2 ?
The solutions to the equation x^2+12^2=15^2 are x=9,x=-9
Find the zeros of x^2+12^2=15^2
The zeros of x^2+12^2=15^2 are x=9,x=-9