What is 1/(sec^2(y))dy ?

The solution to 1/(sec^2(y))dy is cos^2(y)dy

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simplify 1/(sec^2(y))dy

simplify

\frac{1}{sec ^{2} ( y )} d y

cos^{2} (y) d y

Solution steps

\frac{1}{sec ^{2} ( y )} d y

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot d y}{sec ^{2} ( y )}

Multiply:

1 \cdot d y = d y

= \frac{d y}{sec ^{2} ( y )}

Use the basic trigonometric identity:

\frac{1}{sec ( x )} = cos (x)

= d y cos^{2} (y)

sin (π x - π)

sin (arcsec (\frac{x}{7}))

\frac{h}{tan ( 4 0 ^{\circ} )}

1 - sin^{2} (t)

sin (2 π + β^{2})