What is cos((npi)/2)-cos(npi) ?

The solution to cos((npi)/2)-cos(npi) is cos((pin)/2)-(-1)^n

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simplify cos((npi)/2)-cos(npi)

simplify

cos (\frac{nπ}{2}) - cos (nπ)

cos (\frac{πn}{2}) - (- 1)^{n}

Solution steps

cos (\frac{nπ}{2}) - cos (nπ)

Use the basic trigonometric identity:

cos (nπ) = (- 1)^{n}

= cos (\frac{nπ}{2}) - (- 1)^{n}

1 - 2 cos (3 x - π)

\frac{x + π}{cos ( x + π )}

cot^{2} (x) + 1

tan (arccos (\frac{3}{x}))

cos (a - 9 0^{\circ})

What is cos((npi)/2)-cos(npi) ?
The solution to cos((npi)/2)-cos(npi) is cos((pin)/2)-(-1)^n