What are the solutions to the equation 400=30(25-t^2) ?

The solutions to the equation 400=30(25-t^2) are t=sqrt(35/3),t=-sqrt(35/3)

Find the zeros of 400=30(25-t^2)

The zeros of 400=30(25-t^2) are t=sqrt(35/3),t=-sqrt(35/3)

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400 = 30 (25 - t^{2})

t = \frac{35}{3}, t = - \frac{35}{3}

Solution steps

400 = 30 (25 - t^{2})

Switch sides

30 (25 - t^{2}) = 400

Divide both sides by

30

25 - t^{2} = \frac{40}{3}

Move

25

to the right side

- t^{2} = - \frac{35}{3}

Divide both sides by

- 1

t^{2} = \frac{35}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{35}{3}, t = - \frac{35}{3}

\frac{2.5}{2.5 - 3}

\frac{1}{2} - \frac{2}{3} x = \frac{1}{4}

9 n^{2} - 6 n

25 x^{2} - 40 x + 15

- 72 = 6 (- 2 + 5 n)

What are the solutions to the equation 400=30(25-t^2) ?
The solutions to the equation 400=30(25-t^2) are t=sqrt(35/3),t=-sqrt(35/3)
Find the zeros of 400=30(25-t^2)
The zeros of 400=30(25-t^2) are t=sqrt(35/3),t=-sqrt(35/3)