What is 2/(n^2pi)cos(npi) ?

The solution to 2/(n^2pi)cos(npi) is (2(-1)^n)/(pin^2)

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simplify 2/(n^2pi)cos(npi)

simplify

\frac{2}{n ^{2} π} cos (nπ)

\frac{2 ( - 1 ) ^{n}}{π n ^{2}}

Solution steps

\frac{2}{n ^{2} π} cos (nπ)

Use the basic trigonometric identity:

cos (nπ) = (- 1)^{n}

= (- 1)^{n} \frac{2}{π n ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 ( - 1 ) ^{n}}{π n ^{2}}

sin (\frac{1}{tan ( x )})

2 (cos (x - \frac{2 π}{3}) + 2)

sin (\frac{x}{2} - 2 π)

cos (nπ) + cos (- nπ)

cos (θ - 24 0^{\circ})

What is 2/(n^2pi)cos(npi) ?
The solution to 2/(n^2pi)cos(npi) is (2(-1)^n)/(pin^2)