What is sin(pi+θ)+cos(pi/2-θ) ?

The solution to sin(pi+θ)+cos(pi/2-θ) is 0

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simplify sin(pi+θ)+cos(pi/2-θ)

simplify

sin (π + θ) + cos (\frac{π}{2} - θ)

0

Solution steps

sin (π + θ) + cos (\frac{π}{2} - θ)

Rewrite using trig identities

= sin (π + θ) + sin (θ)

Rewrite using trig identities

= - sin (θ) + sin (θ)

Add similar elements:

- sin (θ) + sin (θ) = 0

= 0

2 sin (2 x - \frac{π}{3}) + 1

csc (- θ)

\frac{d x}{cos ^{2} ( x )}

cos (y + π)

sin (n - \frac{π}{2})