What is the answer to (x+7)(x-1)=(x+1)^2 ?

The answer to (x+7)(x-1)=(x+1)^2 is x=2

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(x+7)(x-1)=(x+1)^2

(x + 7) (x - 1) = (x + 1)^{2}

x = 2

Solution steps

(x + 7) (x - 1) = (x + 1)^{2}

Expand

(x + 7) (x - 1) : x^{2} + 6 x - 7

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

x^{2} + 6 x - 7 = x^{2} + 2 x + 1

Move

7

to the right side

x^{2} + 6 x = x^{2} + 2 x + 8

Subtract

x^{2} + 2 x

from both sides

x^{2} + 6 x - (x^{2} + 2 x) = x^{2} + 2 x + 8 - (x^{2} + 2 x)

Simplify

4 x = 8

Divide both sides by

4

x = 2

x w - y w + x z - yz

(x y)^{- 2}

\frac{x ^{- 7}}{x ^{- 9}}

\frac{10 b ^{6}}{( 5 b ^{3} ) ^{3}}

\frac{3}{4} m + 5 = 2

What is the answer to (x+7)(x-1)=(x+1)^2 ?
The answer to (x+7)(x-1)=(x+1)^2 is x=2
Solve for x: (x+7)(x-1)=(x+1)^2
The solution is x=2