What are the solutions to the equation z^2+1=0 ?

The solutions to the equation z^2+1=0 are z=i,z=-i

Find the zeros of z^2+1=0

The zeros of z^2+1=0 are z=i,z=-i

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z^{2} + 1 = 0

z = i, z = - i

Solution steps

z^{2} + 1 = 0

Move

1

to the right side

z^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 1, z = - - 1

- 1 = i

- - 1 = - i

z = i, z = - i

15 y^{2} + 31 y + 2

x - \frac{5 x}{4} + \frac{3}{4} = \frac{3 x}{8} - \frac{3 x}{2} - \frac{7}{8}

\frac{5}{1 - e ^{\frac{1}{- 0.1}}}

12 x^{2} = 0

8 x^{2} - 16 x + 8

What are the solutions to the equation z^2+1=0 ?
The solutions to the equation z^2+1=0 are z=i,z=-i
Find the zeros of z^2+1=0
The zeros of z^2+1=0 are z=i,z=-i