What is (sin(2x-3pi))/(2x-pi) ?

The solution to (sin(2x-3pi))/(2x-pi) is -(sin(2x))/(2x-pi)

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simplify (sin(2x-3pi))/(2x-pi)

simplify

\frac{sin ( 2 x - 3 π )}{2 x - π}

- \frac{sin ( 2 x )}{2 x - π}

Solution steps

\frac{sin ( 2 x - 3 π )}{2 x - π}

Rewrite using trig identities

= \frac{- sin ( 2 x )}{2 x - π}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{sin ( 2 x )}{2 x - π}

sin (arccos (1 - \frac{y}{r}))

(3)^{2} + (- 3 tan (t))^{2}

cos (\frac{π}{2} - 2 x)

cos (- 2 nπ)

f (x) = cos (9 0^{\circ} + arccos (x))

What is (sin(2x-3pi))/(2x-pi) ?
The solution to (sin(2x-3pi))/(2x-pi) is -(sin(2x))/(2x-pi)