What is (sin(pi+x))/(cos(2pi+x)) ?

The solution to (sin(pi+x))/(cos(2pi+x)) is -tan(x)

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simplify (sin(pi+x))/(cos(2pi+x))

simplify

\frac{sin ( π + x )}{cos ( 2 π + x )}

- tan (x)

Solution steps

\frac{sin ( π + x )}{cos ( 2 π + x )}

Rewrite using trig identities

= \frac{sin ( π + x )}{cos ( x )}

Rewrite using trig identities

= \frac{- sin ( x )}{cos ( x )}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{sin ( x )}{cos ( x )}

Rewrite using trig identities

= - tan (x)

ln (1 - sin^{2} (x))

\frac{1}{2} tan (x - \frac{π}{4})

sin (a - 3 0^{\circ})

sin (\frac{π}{2} - arcsin (x))

sec (- 4 x)

What is (sin(pi+x))/(cos(2pi+x)) ?
The solution to (sin(pi+x))/(cos(2pi+x)) is -tan(x)