What is sin(npi-(pi/2)) ?

The solution to sin(npi-(pi/2)) is -(-1)^n

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simplify sin(npi-(pi/2))

simplify

sin (nπ - (\frac{π}{2}))

- (- 1)^{n}

Solution steps

sin (nπ - (\frac{π}{2}))

Rewrite using trig identities

= - cos (πn)

Use the basic trigonometric identity:

cos (nπ) = (- 1)^{n}

= - (- 1)^{n}

sin (- arctan (x))

tan (a - 9 0^{\circ}) sin (- a)

cos (arccos (8 x))

sin (g + π)

sin^{2} (9 0^{\circ} - x)