What are the solutions to the equation 25y^2+1=0 ?

The solutions to the equation 25y^2+1=0 are y= 1/5 i,y=-1/5 i

Find the zeros of 25y^2+1=0

The zeros of 25y^2+1=0 are y= 1/5 i,y=-1/5 i

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25 y^{2} + 1 = 0

y = \frac{1}{5} i, y = - \frac{1}{5} i

Solution steps

25 y^{2} + 1 = 0

Move

1

to the right side

25 y^{2} = - 1

Divide both sides by

25

y^{2} = - \frac{1}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{1}{25}, y = - - \frac{1}{25}

- \frac{1}{25} = \frac{1}{5} i

- - \frac{1}{25} = - \frac{1}{5} i

y = \frac{1}{5} i, y = - \frac{1}{5} i

8 - 6 x > - 18

23 - 7 x = - 1 - (3 x - 4)

\frac{4 x}{5} - x = \frac{x}{10} - \frac{15}{2}

(4 y + 3) (2 - y) = 0

What are the solutions to the equation 25y^2+1=0 ?
The solutions to the equation 25y^2+1=0 are y= 1/5 i,y=-1/5 i
Find the zeros of 25y^2+1=0
The zeros of 25y^2+1=0 are y= 1/5 i,y=-1/5 i