What is (t^2)/(sin^2(t))dt ?

The solution to (t^2)/(sin^2(t))dt is t^2csc^2(t)dt

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simplify (t^2)/(sin^2(t))dt

simplify

\frac{t ^{2}}{sin ^{2} ( t )} d t

t^{2} csc^{2} (t) d t

Solution steps

\frac{t ^{2}}{sin ^{2} ( t )} d t

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{t ^{2} d t}{sin ^{2} ( t )}

Use the basic trigonometric identity:

\frac{1}{sin ( x )} = csc (x)

= t^{2} d t csc^{2} (t)

cos (4 π t + 5 π)

sin (36 0^{\circ} + θ)

sin (- 4 t)

cot (9 0^{\circ} - θ) + cot (θ)

sin ((\frac{π}{2}) + n \cdot π)

What is (t^2)/(sin^2(t))dt ?
The solution to (t^2)/(sin^2(t))dt is t^2csc^2(t)dt